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8y+22=2(y-4)
We move all terms to the left:
8y+22-(2(y-4))=0
We calculate terms in parentheses: -(2(y-4)), so:We get rid of parentheses
2(y-4)
We multiply parentheses
2y-8
Back to the equation:
-(2y-8)
8y-2y+8+22=0
We add all the numbers together, and all the variables
6y+30=0
We move all terms containing y to the left, all other terms to the right
6y=-30
y=-30/6
y=-5
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