8y+22=2(y-4)

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Solution for 8y+22=2(y-4) equation: 



8y+22=2(y-4)

We move all terms to the left:

8y+22-(2(y-4))=0



We calculate terms in parentheses: -(2(y-4)), so:

2(y-4)

We multiply parentheses

2y-8

Back to the equation:

-(2y-8)



We get rid of parentheses

8y-2y+8+22=0

We add all the numbers together, and all the variables

6y+30=0

We move all terms containing y to the left, all other terms to the right

6y=-30

y=-30/6

y=-5

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