8y+28=-4(y-1)

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Solution for 8y+28=-4(y-1) equation: 



8y+28=-4(y-1)

We move all terms to the left:

8y+28-(-4(y-1))=0



We calculate terms in parentheses: -(-4(y-1)), so:

-4(y-1)

We multiply parentheses

-4y+4

Back to the equation:

-(-4y+4)



We get rid of parentheses

8y+4y-4+28=0

We add all the numbers together, and all the variables

12y+24=0

We move all terms containing y to the left, all other terms to the right

12y=-24

y=-24/12

y=-2

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