8y+2=2y+4(y+3)

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Solution for 8y+2=2y+4(y+3) equation: 



8y+2=2y+4(y+3)

We move all terms to the left:

8y+2-(2y+4(y+3))=0



We calculate terms in parentheses: -(2y+4(y+3)), so:

2y+4(y+3)

We multiply parentheses

2y+4y+12

We add all the numbers together, and all the variables

6y+12

Back to the equation:

-(6y+12)



We get rid of parentheses

8y-6y-12+2=0

We add all the numbers together, and all the variables

2y-10=0

We move all terms containing y to the left, all other terms to the right

2y=10

y=10/2

y=5

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