8y+2=5(y-2)

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Solution for 8y+2=5(y-2) equation: 



8y+2=5(y-2)

We move all terms to the left:

8y+2-(5(y-2))=0



We calculate terms in parentheses: -(5(y-2)), so:

5(y-2)

We multiply parentheses

5y-10

Back to the equation:

-(5y-10)



We get rid of parentheses

8y-5y+10+2=0

We add all the numbers together, and all the variables

3y+12=0

We move all terms containing y to the left, all other terms to the right

3y=-12

y=-12/3

y=-4

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