8y+3(4-6)=3(y+1)-2

Solution for 8y+3(4-6)=3(y+1)-2 equation:

Simplifying
8y + 3(4 + -6) = 3(y + 1) + -2

Combine like terms: 4 + -6 = -2
8y + 3(-2) = 3(y + 1) + -2

Multiply 3 * -2
8y + -6 = 3(y + 1) + -2

Reorder the terms:
-6 + 8y = 3(y + 1) + -2

Reorder the terms:
-6 + 8y = 3(1 + y) + -2
-6 + 8y = (1 * 3 + y * 3) + -2
-6 + 8y = (3 + 3y) + -2

Reorder the terms:
-6 + 8y = 3 + -2 + 3y

Combine like terms: 3 + -2 = 1
-6 + 8y = 1 + 3y

Solving
-6 + 8y = 1 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-6 + 8y + -3y = 1 + 3y + -3y

Combine like terms: 8y + -3y = 5y
-6 + 5y = 1 + 3y + -3y

Combine like terms: 3y + -3y = 0
-6 + 5y = 1 + 0
-6 + 5y = 1

Add '6' to each side of the equation.
-6 + 6 + 5y = 1 + 6

Combine like terms: -6 + 6 = 0
0 + 5y = 1 + 6
5y = 1 + 6

Combine like terms: 1 + 6 = 7
5y = 7

Divide each side by '5'.
y = 1.4

Simplifying
y = 1.4