8y+3(y-2)=4(y+1)-2

Solution for 8y+3(y-2)=4(y+1)-2 equation:

Simplifying
8y + 3(y + -2) = 4(y + 1) + -2

Reorder the terms:
8y + 3(-2 + y) = 4(y + 1) + -2
8y + (-2 * 3 + y * 3) = 4(y + 1) + -2
8y + (-6 + 3y) = 4(y + 1) + -2

Reorder the terms:
-6 + 8y + 3y = 4(y + 1) + -2

Combine like terms: 8y + 3y = 11y
-6 + 11y = 4(y + 1) + -2

Reorder the terms:
-6 + 11y = 4(1 + y) + -2
-6 + 11y = (1 * 4 + y * 4) + -2
-6 + 11y = (4 + 4y) + -2

Reorder the terms:
-6 + 11y = 4 + -2 + 4y

Combine like terms: 4 + -2 = 2
-6 + 11y = 2 + 4y

Solving
-6 + 11y = 2 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
-6 + 11y + -4y = 2 + 4y + -4y

Combine like terms: 11y + -4y = 7y
-6 + 7y = 2 + 4y + -4y

Combine like terms: 4y + -4y = 0
-6 + 7y = 2 + 0
-6 + 7y = 2

Add '6' to each side of the equation.
-6 + 6 + 7y = 2 + 6

Combine like terms: -6 + 6 = 0
0 + 7y = 2 + 6
7y = 2 + 6

Combine like terms: 2 + 6 = 8
7y = 8

Divide each side by '7'.
y = 1.142857143

Simplifying
y = 1.142857143