8y+3(y-4)=6(y+1)-2

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Solution for 8y+3(y-4)=6(y+1)-2 equation:


Simplifying
8y + 3(y + -4) = 6(y + 1) + -2

Reorder the terms:
8y + 3(-4 + y) = 6(y + 1) + -2
8y + (-4 * 3 + y * 3) = 6(y + 1) + -2
8y + (-12 + 3y) = 6(y + 1) + -2

Reorder the terms:
-12 + 8y + 3y = 6(y + 1) + -2

Combine like terms: 8y + 3y = 11y
-12 + 11y = 6(y + 1) + -2

Reorder the terms:
-12 + 11y = 6(1 + y) + -2
-12 + 11y = (1 * 6 + y * 6) + -2
-12 + 11y = (6 + 6y) + -2

Reorder the terms:
-12 + 11y = 6 + -2 + 6y

Combine like terms: 6 + -2 = 4
-12 + 11y = 4 + 6y

Solving
-12 + 11y = 4 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
-12 + 11y + -6y = 4 + 6y + -6y

Combine like terms: 11y + -6y = 5y
-12 + 5y = 4 + 6y + -6y

Combine like terms: 6y + -6y = 0
-12 + 5y = 4 + 0
-12 + 5y = 4

Add '12' to each side of the equation.
-12 + 12 + 5y = 4 + 12

Combine like terms: -12 + 12 = 0
0 + 5y = 4 + 12
5y = 4 + 12

Combine like terms: 4 + 12 = 16
5y = 16

Divide each side by '5'.
y = 3.2

Simplifying
y = 3.2

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