8y+3(y-7)=(y+2)-2

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Solution for 8y+3(y-7)=(y+2)-2 equation: 



8y+3(y-7)=(y+2)-2

We move all terms to the left:

8y+3(y-7)-((y+2)-2)=0

We multiply parentheses

8y+3y-((y+2)-2)-21=0



We calculate terms in parentheses: -((y+2)-2), so:

(y+2)-2

We get rid of parentheses

y+2-2

We add all the numbers together, and all the variables

y

Back to the equation:

-(y)



We add all the numbers together, and all the variables

10y-21=0

We move all terms containing y to the left, all other terms to the right

10y=21

y=21/10

y=2+1/10

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