8y+33=-5(y-4)

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Solution for 8y+33=-5(y-4) equation: 



8y+33=-5(y-4)

We move all terms to the left:

8y+33-(-5(y-4))=0



We calculate terms in parentheses: -(-5(y-4)), so:

-5(y-4)

We multiply parentheses

-5y+20

Back to the equation:

-(-5y+20)



We get rid of parentheses

8y+5y-20+33=0

We add all the numbers together, and all the variables

13y+13=0

We move all terms containing y to the left, all other terms to the right

13y=-13

y=-13/13

y=-1

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