8y+38=2(y-5)

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Solution for 8y+38=2(y-5) equation: 



8y+38=2(y-5)

We move all terms to the left:

8y+38-(2(y-5))=0



We calculate terms in parentheses: -(2(y-5)), so:

2(y-5)

We multiply parentheses

2y-10

Back to the equation:

-(2y-10)



We get rid of parentheses

8y-2y+10+38=0

We add all the numbers together, and all the variables

6y+48=0

We move all terms containing y to the left, all other terms to the right

6y=-48

y=-48/6

y=-8

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