8y+3=3(2y+12)

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Solution for 8y+3=3(2y+12) equation: 



8y+3=3(2y+12)

We move all terms to the left:

8y+3-(3(2y+12))=0



We calculate terms in parentheses: -(3(2y+12)), so:

3(2y+12)

We multiply parentheses

6y+36

Back to the equation:

-(6y+36)



We get rid of parentheses

8y-6y-36+3=0

We add all the numbers together, and all the variables

2y-33=0

We move all terms containing y to the left, all other terms to the right

2y=33

y=33/2

y=16+1/2

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