8y+4(2+y)=3(y-1)+10y

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Solution for 8y+4(2+y)=3(y-1)+10y equation: 



8y+4(2+y)=3(y-1)+10y

We move all terms to the left:

8y+4(2+y)-(3(y-1)+10y)=0

We add all the numbers together, and all the variables

8y+4(y+2)-(3(y-1)+10y)=0

We multiply parentheses

8y+4y-(3(y-1)+10y)+8=0



We calculate terms in parentheses: -(3(y-1)+10y), so:

3(y-1)+10y

We add all the numbers together, and all the variables

10y+3(y-1)

We multiply parentheses

10y+3y-3

We add all the numbers together, and all the variables

13y-3

Back to the equation:

-(13y-3)



We add all the numbers together, and all the variables

12y-(13y-3)+8=0

We get rid of parentheses

12y-13y+3+8=0

We add all the numbers together, and all the variables

-1y+11=0

We move all terms containing y to the left, all other terms to the right

-y=-11

y=-11/-1

y=+11

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