8y+4(3+y)=3(y-4)+10y

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Solution for 8y+4(3+y)=3(y-4)+10y equation: 



8y+4(3+y)=3(y-4)+10y

We move all terms to the left:

8y+4(3+y)-(3(y-4)+10y)=0

We add all the numbers together, and all the variables

8y+4(y+3)-(3(y-4)+10y)=0

We multiply parentheses

8y+4y-(3(y-4)+10y)+12=0



We calculate terms in parentheses: -(3(y-4)+10y), so:

3(y-4)+10y

We add all the numbers together, and all the variables

10y+3(y-4)

We multiply parentheses

10y+3y-12

We add all the numbers together, and all the variables

13y-12

Back to the equation:

-(13y-12)



We add all the numbers together, and all the variables

12y-(13y-12)+12=0

We get rid of parentheses

12y-13y+12+12=0

We add all the numbers together, and all the variables

-1y+24=0

We move all terms containing y to the left, all other terms to the right

-y=-24

y=-24/-1

y=+24

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