8y+4(3y-23)=436

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Solution for 8y+4(3y-23)=436 equation: 



8y+4(3y-23)=436

We move all terms to the left:

8y+4(3y-23)-(436)=0

We multiply parentheses

8y+12y-92-436=0

We add all the numbers together, and all the variables

20y-528=0

We move all terms containing y to the left, all other terms to the right

20y=528

y=528/20

y=26+2/5

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