8y+4(4+y)=3(y-3)+10y

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Solution for 8y+4(4+y)=3(y-3)+10y equation: 



8y+4(4+y)=3(y-3)+10y

We move all terms to the left:

8y+4(4+y)-(3(y-3)+10y)=0

We add all the numbers together, and all the variables

8y+4(y+4)-(3(y-3)+10y)=0

We multiply parentheses

8y+4y-(3(y-3)+10y)+16=0



We calculate terms in parentheses: -(3(y-3)+10y), so:

3(y-3)+10y

We add all the numbers together, and all the variables

10y+3(y-3)

We multiply parentheses

10y+3y-9

We add all the numbers together, and all the variables

13y-9

Back to the equation:

-(13y-9)



We add all the numbers together, and all the variables

12y-(13y-9)+16=0

We get rid of parentheses

12y-13y+9+16=0

We add all the numbers together, and all the variables

-1y+25=0

We move all terms containing y to the left, all other terms to the right

-y=-25

y=-25/-1

y=+25

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