8y+4(4y-3)=4(6y-4)+4

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Solution for 8y+4(4y-3)=4(6y-4)+4 equation: 



8y+4(4y-3)=4(6y-4)+4

We move all terms to the left:

8y+4(4y-3)-(4(6y-4)+4)=0

We multiply parentheses

8y+16y-(4(6y-4)+4)-12=0



We calculate terms in parentheses: -(4(6y-4)+4), so:

4(6y-4)+4

We multiply parentheses

24y-16+4

We add all the numbers together, and all the variables

24y-12

Back to the equation:

-(24y-12)



We add all the numbers together, and all the variables

24y-(24y-12)-12=0

We get rid of parentheses

24y-24y+12-12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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