8y+4(8+y)=3(y-6)+10y

Solution for 8y+4(8+y)=3(y-6)+10y equation:

8y+4(8+y)=3(y-6)+10y

We move all terms to the left:

8y+4(8+y)-(3(y-6)+10y)=0

We add all the numbers together, and all the variables

8y+4(y+8)-(3(y-6)+10y)=0

We multiply parentheses

8y+4y-(3(y-6)+10y)+32=0


We calculate terms in parentheses: -(3(y-6)+10y), so:

3(y-6)+10y

We add all the numbers together, and all the variables

10y+3(y-6)

We multiply parentheses

10y+3y-18

We add all the numbers together, and all the variables

13y-18

Back to the equation:

-(13y-18)


We add all the numbers together, and all the variables

12y-(13y-18)+32=0

We get rid of parentheses

12y-13y+18+32=0

We add all the numbers together, and all the variables

-1y+50=0

We move all terms containing y to the left, all other terms to the right

-y=-50

y=-50/-1

y=+50