8y+42=-2(y-1)

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Solution for 8y+42=-2(y-1) equation: 



8y+42=-2(y-1)

We move all terms to the left:

8y+42-(-2(y-1))=0



We calculate terms in parentheses: -(-2(y-1)), so:

-2(y-1)

We multiply parentheses

-2y+2

Back to the equation:

-(-2y+2)



We get rid of parentheses

8y+2y-2+42=0

We add all the numbers together, and all the variables

10y+40=0

We move all terms containing y to the left, all other terms to the right

10y=-40

y=-40/10

y=-4

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