8y+4=-3(y-1)+7

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Solution for 8y+4=-3(y-1)+7 equation: 



8y+4=-3(y-1)+7

We move all terms to the left:

8y+4-(-3(y-1)+7)=0



We calculate terms in parentheses: -(-3(y-1)+7), so:

-3(y-1)+7

We multiply parentheses

-3y+3+7

We add all the numbers together, and all the variables

-3y+10

Back to the equation:

-(-3y+10)



We get rid of parentheses

8y+3y-10+4=0

We add all the numbers together, and all the variables

11y-6=0

We move all terms containing y to the left, all other terms to the right

11y=6

y=6/11

y=6/11

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