8y+4=4(y-3)

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Solution for 8y+4=4(y-3) equation:



8y+4=4(y-3)
We move all terms to the left:
8y+4-(4(y-3))=0
We calculate terms in parentheses: -(4(y-3)), so:
4(y-3)
We multiply parentheses
4y-12
Back to the equation:
-(4y-12)
We get rid of parentheses
8y-4y+12+4=0
We add all the numbers together, and all the variables
4y+16=0
We move all terms containing y to the left, all other terms to the right
4y=-16
y=-16/4
y=-4

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