8y+4=5(y-1)+7

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Solution for 8y+4=5(y-1)+7 equation:



8y+4=5(y-1)+7
We move all terms to the left:
8y+4-(5(y-1)+7)=0
We calculate terms in parentheses: -(5(y-1)+7), so:
5(y-1)+7
We multiply parentheses
5y-5+7
We add all the numbers together, and all the variables
5y+2
Back to the equation:
-(5y+2)
We get rid of parentheses
8y-5y-2+4=0
We add all the numbers together, and all the variables
3y+2=0
We move all terms containing y to the left, all other terms to the right
3y=-2
y=-2/3
y=-2/3

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