8y+8=2(y+1)

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Solution for 8y+8=2(y+1) equation: 



8y+8=2(y+1)

We move all terms to the left:

8y+8-(2(y+1))=0



We calculate terms in parentheses: -(2(y+1)), so:

2(y+1)

We multiply parentheses

2y+2

Back to the equation:

-(2y+2)



We get rid of parentheses

8y-2y-2+8=0

We add all the numbers together, and all the variables

6y+6=0

We move all terms containing y to the left, all other terms to the right

6y=-6

y=-6/6

y=-1

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