8y-10-5y=5(2y+4)-2

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Solution for 8y-10-5y=5(2y+4)-2 equation: 



8y-10-5y=5(2y+4)-2

We move all terms to the left:

8y-10-5y-(5(2y+4)-2)=0

We add all the numbers together, and all the variables

3y-(5(2y+4)-2)-10=0



We calculate terms in parentheses: -(5(2y+4)-2), so:

5(2y+4)-2

We multiply parentheses

10y+20-2

We add all the numbers together, and all the variables

10y+18

Back to the equation:

-(10y+18)



We get rid of parentheses

3y-10y-18-10=0

We add all the numbers together, and all the variables

-7y-28=0

We move all terms containing y to the left, all other terms to the right

-7y=28

y=28/-7

y=-4

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