8y-10=2(4y-5)

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Solution for 8y-10=2(4y-5) equation:


Simplifying
8y + -10 = 2(4y + -5)

Reorder the terms:
-10 + 8y = 2(4y + -5)

Reorder the terms:
-10 + 8y = 2(-5 + 4y)
-10 + 8y = (-5 * 2 + 4y * 2)
-10 + 8y = (-10 + 8y)

Add '10' to each side of the equation.
-10 + 10 + 8y = -10 + 10 + 8y

Combine like terms: -10 + 10 = 0
0 + 8y = -10 + 10 + 8y
8y = -10 + 10 + 8y

Combine like terms: -10 + 10 = 0
8y = 0 + 8y
8y = 8y

Add '-8y' to each side of the equation.
8y + -8y = 8y + -8y

Combine like terms: 8y + -8y = 0
0 = 8y + -8y

Combine like terms: 8y + -8y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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