8y-11=6(y-5)+2

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Solution for 8y-11=6(y-5)+2 equation: 



8y-11=6(y-5)+2

We move all terms to the left:

8y-11-(6(y-5)+2)=0



We calculate terms in parentheses: -(6(y-5)+2), so:

6(y-5)+2

We multiply parentheses

6y-30+2

We add all the numbers together, and all the variables

6y-28

Back to the equation:

-(6y-28)



We get rid of parentheses

8y-6y+28-11=0

We add all the numbers together, and all the variables

2y+17=0

We move all terms containing y to the left, all other terms to the right

2y=-17

y=-17/2

y=-8+1/2

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