8y-12-4y=4(y-3)

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Solution for 8y-12-4y=4(y-3) equation:



8y-12-4y=4(y-3)
We move all terms to the left:
8y-12-4y-(4(y-3))=0
We add all the numbers together, and all the variables
4y-(4(y-3))-12=0
We calculate terms in parentheses: -(4(y-3)), so:
4(y-3)
We multiply parentheses
4y-12
Back to the equation:
-(4y-12)
We get rid of parentheses
4y-4y+12-12=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0

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