8y-12=3(y+6)

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Solution for 8y-12=3(y+6) equation: 



8y-12=3(y+6)

We move all terms to the left:

8y-12-(3(y+6))=0



We calculate terms in parentheses: -(3(y+6)), so:

3(y+6)

We multiply parentheses

3y+18

Back to the equation:

-(3y+18)



We get rid of parentheses

8y-3y-18-12=0

We add all the numbers together, and all the variables

5y-30=0

We move all terms containing y to the left, all other terms to the right

5y=30

y=30/5

y=6

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