8y-1=4(2y+1)-5

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Solution for 8y-1=4(2y+1)-5 equation: 



8y-1=4(2y+1)-5

We move all terms to the left:

8y-1-(4(2y+1)-5)=0



We calculate terms in parentheses: -(4(2y+1)-5), so:

4(2y+1)-5

We multiply parentheses

8y+4-5

We add all the numbers together, and all the variables

8y-1

Back to the equation:

-(8y-1)



We get rid of parentheses

8y-8y+1-1=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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