8y-2(7+3y)=8+4y

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Solution for 8y-2(7+3y)=8+4y equation:



8y-2(7+3y)=8+4y
We move all terms to the left:
8y-2(7+3y)-(8+4y)=0
We add all the numbers together, and all the variables
8y-2(3y+7)-(4y+8)=0
We multiply parentheses
8y-6y-(4y+8)-14=0
We get rid of parentheses
8y-6y-4y-8-14=0
We add all the numbers together, and all the variables
-2y-22=0
We move all terms containing y to the left, all other terms to the right
-2y=22
y=22/-2
y=-11

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