8y-2(7+3y)=8+4y

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Solution for 8y-2(7+3y)=8+4y equation: 



8y-2(7+3y)=8+4y

We move all terms to the left:

8y-2(7+3y)-(8+4y)=0

We add all the numbers together, and all the variables

8y-2(3y+7)-(4y+8)=0

We multiply parentheses

8y-6y-(4y+8)-14=0

We get rid of parentheses

8y-6y-4y-8-14=0

We add all the numbers together, and all the variables

-2y-22=0

We move all terms containing y to the left, all other terms to the right

-2y=22

y=22/-2

y=-11

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