8y-28=4(2y-7)

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Solution for 8y-28=4(2y-7) equation: 



8y-28=4(2y-7)

We move all terms to the left:

8y-28-(4(2y-7))=0



We calculate terms in parentheses: -(4(2y-7)), so:

4(2y-7)

We multiply parentheses

8y-28

Back to the equation:

-(8y-28)



We get rid of parentheses

8y-8y+28-28=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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