8y-28=6(y-8)

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Solution for 8y-28=6(y-8) equation: 



8y-28=6(y-8)

We move all terms to the left:

8y-28-(6(y-8))=0



We calculate terms in parentheses: -(6(y-8)), so:

6(y-8)

We multiply parentheses

6y-48

Back to the equation:

-(6y-48)



We get rid of parentheses

8y-6y+48-28=0

We add all the numbers together, and all the variables

2y+20=0

We move all terms containing y to the left, all other terms to the right

2y=-20

y=-20/2

y=-10

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