8y-3(3y+2)=6

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Solution for 8y-3(3y+2)=6 equation: 



8y-3(3y+2)=6

We move all terms to the left:

8y-3(3y+2)-(6)=0

We multiply parentheses

8y-9y-6-6=0

We add all the numbers together, and all the variables

-1y-12=0

We move all terms containing y to the left, all other terms to the right

-y=12

y=12/-1

y=-12

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