8y-3(4-2y)=6(y+1)-2

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Solution for 8y-3(4-2y)=6(y+1)-2 equation:


Simplifying
8y + -3(4 + -2y) = 6(y + 1) + -2
8y + (4 * -3 + -2y * -3) = 6(y + 1) + -2
8y + (-12 + 6y) = 6(y + 1) + -2

Reorder the terms:
-12 + 8y + 6y = 6(y + 1) + -2

Combine like terms: 8y + 6y = 14y
-12 + 14y = 6(y + 1) + -2

Reorder the terms:
-12 + 14y = 6(1 + y) + -2
-12 + 14y = (1 * 6 + y * 6) + -2
-12 + 14y = (6 + 6y) + -2

Reorder the terms:
-12 + 14y = 6 + -2 + 6y

Combine like terms: 6 + -2 = 4
-12 + 14y = 4 + 6y

Solving
-12 + 14y = 4 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
-12 + 14y + -6y = 4 + 6y + -6y

Combine like terms: 14y + -6y = 8y
-12 + 8y = 4 + 6y + -6y

Combine like terms: 6y + -6y = 0
-12 + 8y = 4 + 0
-12 + 8y = 4

Add '12' to each side of the equation.
-12 + 12 + 8y = 4 + 12

Combine like terms: -12 + 12 = 0
0 + 8y = 4 + 12
8y = 4 + 12

Combine like terms: 4 + 12 = 16
8y = 16

Divide each side by '8'.
y = 2

Simplifying
y = 2

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