8y-3(4-2y)=6*y+1)-2

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Solution for 8y-3(4-2y)=6*y+1)-2 equation: 



8y-3(4-2y)=6y+1)-2

We move all terms to the left:

8y-3(4-2y)-(6y+1)-2)=0

We add all the numbers together, and all the variables

8y-3(-2y+4)-(6y+1)-2)=0

We add all the numbers together, and all the variables

8y-3(-2y+4)-(6y+1)=0

We multiply parentheses

8y+6y-(6y+1)-12=0

We get rid of parentheses

8y+6y-6y-1-12=0

We add all the numbers together, and all the variables

8y-13=0

We move all terms containing y to the left, all other terms to the right

8y=13

y=13/8

y=1+5/8

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