8y-3(4-2y)=6*y+1)-2

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Solution for 8y-3(4-2y)=6*y+1)-2 equation:



8y-3(4-2y)=6y+1)-2
We move all terms to the left:
8y-3(4-2y)-(6y+1)-2)=0
We add all the numbers together, and all the variables
8y-3(-2y+4)-(6y+1)-2)=0
We add all the numbers together, and all the variables
8y-3(-2y+4)-(6y+1)=0
We multiply parentheses
8y+6y-(6y+1)-12=0
We get rid of parentheses
8y+6y-6y-1-12=0
We add all the numbers together, and all the variables
8y-13=0
We move all terms containing y to the left, all other terms to the right
8y=13
y=13/8
y=1+5/8

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