8y-30=6(y-5)C

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Solution for 8y-30=6(y-5)C equation: 



8y-30=6(y-5)

We move all terms to the left:

8y-30-(6(y-5))=0



We calculate terms in parentheses: -(6(y-5)), so:

6(y-5)

We multiply parentheses

6y-30

Back to the equation:

-(6y-30)



We get rid of parentheses

8y-6y+30-30=0

We add all the numbers together, and all the variables

2y=0

y=0/2

y=0

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