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8y-3=5(5y-1)+3y
We move all terms to the left:
8y-3-(5(5y-1)+3y)=0
We calculate terms in parentheses: -(5(5y-1)+3y), so:We get rid of parentheses
5(5y-1)+3y
We add all the numbers together, and all the variables
3y+5(5y-1)
We multiply parentheses
3y+25y-5
We add all the numbers together, and all the variables
28y-5
Back to the equation:
-(28y-5)
8y-28y+5-3=0
We add all the numbers together, and all the variables
-20y+2=0
We move all terms containing y to the left, all other terms to the right
-20y=-2
y=-2/-20
y=1/10
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