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8y-3=5(y-1)/3y
We move all terms to the left:
8y-3-(5(y-1)/3y)=0
Domain of the equation: 3y)!=0We multiply all the terms by the denominator
y!=0/1
y!=0
y∈R
8y*3y)-(5(y-1)-3*3y)=0
Wy multiply elements
24y^2-9y=0
a = 24; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·24·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*24}=\frac{0}{48} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*24}=\frac{18}{48} =3/8 $
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