8y-4(2+3y)=4+2(2-y)

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Solution for 8y-4(2+3y)=4+2(2-y) equation: 



8y-4(2+3y)=4+2(2-y)

We move all terms to the left:

8y-4(2+3y)-(4+2(2-y))=0

We add all the numbers together, and all the variables

8y-4(3y+2)-(4+2(-1y+2))=0

We multiply parentheses

8y-12y-(4+2(-1y+2))-8=0



We calculate terms in parentheses: -(4+2(-1y+2)), so:

4+2(-1y+2)

determiningTheFunctionDomain
2(-1y+2)+4

We multiply parentheses

-2y+4+4

We add all the numbers together, and all the variables

-2y+8

Back to the equation:

-(-2y+8)



We add all the numbers together, and all the variables

-4y-(-2y+8)-8=0

We get rid of parentheses

-4y+2y-8-8=0

We add all the numbers together, and all the variables

-2y-16=0

We move all terms containing y to the left, all other terms to the right

-2y=16

y=16/-2

y=-8

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