8y-4(3y+5)=8-(10+10y)

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Solution for 8y-4(3y+5)=8-(10+10y) equation: 



8y-4(3y+5)=8-(10+10y)

We move all terms to the left:

8y-4(3y+5)-(8-(10+10y))=0

We add all the numbers together, and all the variables

8y-4(3y+5)-(8-(10y+10))=0

We multiply parentheses

8y-12y-(8-(10y+10))-20=0



We calculate terms in parentheses: -(8-(10y+10)), so:

8-(10y+10)

determiningTheFunctionDomain
-(10y+10)+8

We get rid of parentheses

-10y-10+8

We add all the numbers together, and all the variables

-10y-2

Back to the equation:

-(-10y-2)



We add all the numbers together, and all the variables

-4y-(-10y-2)-20=0

We get rid of parentheses

-4y+10y+2-20=0

We add all the numbers together, and all the variables

6y-18=0

We move all terms containing y to the left, all other terms to the right

6y=18

y=18/6

y=3

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