8y-4+3(2y+3)=-4(y+1)

Solution for 8y-4+3(2y+3)=-4(y+1) equation:

8y-4+3(2y+3)=-4(y+1)

We move all terms to the left:

8y-4+3(2y+3)-(-4(y+1))=0

We multiply parentheses

8y+6y-(-4(y+1))+9-4=0


We calculate terms in parentheses: -(-4(y+1)), so:

-4(y+1)

We multiply parentheses

-4y-4

Back to the equation:

-(-4y-4)


We add all the numbers together, and all the variables

14y-(-4y-4)+5=0

We get rid of parentheses

14y+4y+4+5=0

We add all the numbers together, and all the variables

18y+9=0

We move all terms containing y to the left, all other terms to the right

18y=-9

y=-9/18

y=-1/2