8y-4+3(y+7)=6y-3(y+3)

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Solution for 8y-4+3(y+7)=6y-3(y+3) equation: 



8y-4+3(y+7)=6y-3(y+3)

We move all terms to the left:

8y-4+3(y+7)-(6y-3(y+3))=0

We multiply parentheses

8y+3y-(6y-3(y+3))+21-4=0



We calculate terms in parentheses: -(6y-3(y+3)), so:

6y-3(y+3)

We multiply parentheses

6y-3y-9

We add all the numbers together, and all the variables

3y-9

Back to the equation:

-(3y-9)



We add all the numbers together, and all the variables

11y-(3y-9)+17=0

We get rid of parentheses

11y-3y+9+17=0

We add all the numbers together, and all the variables

8y+26=0

We move all terms containing y to the left, all other terms to the right

8y=-26

y=-26/8

y=-3+1/4

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