8y-4/4y=0

Solution for 8y-4/4y=0 equation:

8y-4/4y=0


Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R


We multiply all the terms by the denominator


8y*4y-4=0

Wy multiply elements

32y^2-4=0

a = 32; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·32·(-4)
Δ = 512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{512}=\sqrt{256*2}=\sqrt{256}*\sqrt{2}=16\sqrt{2}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{2}}{2*32}=\frac{0-16\sqrt{2}}{64}
=-\frac{16\sqrt{2}}{64}
=-\frac{\sqrt{2}}{4}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{2}}{2*32}=\frac{0+16\sqrt{2}}{64}
=\frac{16\sqrt{2}}{64}
=\frac{\sqrt{2}}{4}
$