8y-41=-5(y+3)

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Solution for 8y-41=-5(y+3) equation: 



8y-41=-5(y+3)

We move all terms to the left:

8y-41-(-5(y+3))=0



We calculate terms in parentheses: -(-5(y+3)), so:

-5(y+3)

We multiply parentheses

-5y-15

Back to the equation:

-(-5y-15)



We get rid of parentheses

8y+5y+15-41=0

We add all the numbers together, and all the variables

13y-26=0

We move all terms containing y to the left, all other terms to the right

13y=26

y=26/13

y=2

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