8y-5(2+y)=2(y+1)

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Solution for 8y-5(2+y)=2(y+1) equation: 



8y-5(2+y)=2(y+1)

We move all terms to the left:

8y-5(2+y)-(2(y+1))=0

We add all the numbers together, and all the variables

8y-5(y+2)-(2(y+1))=0

We multiply parentheses

8y-5y-(2(y+1))-10=0



We calculate terms in parentheses: -(2(y+1)), so:

2(y+1)

We multiply parentheses

2y+2

Back to the equation:

-(2y+2)



We add all the numbers together, and all the variables

3y-(2y+2)-10=0

We get rid of parentheses

3y-2y-2-10=0

We add all the numbers together, and all the variables

y-12=0

We move all terms containing y to the left, all other terms to the right

y=12

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