8y-5(2y+4)=40

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Solution for 8y-5(2y+4)=40 equation: 



8y-5(2y+4)=40

We move all terms to the left:

8y-5(2y+4)-(40)=0

We multiply parentheses

8y-10y-20-40=0

We add all the numbers together, and all the variables

-2y-60=0

We move all terms containing y to the left, all other terms to the right

-2y=60

y=60/-2

y=-30

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