8y-5(y-2)=2*(y+12)-2

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Solution for 8y-5(y-2)=2*(y+12)-2 equation: 



8y-5(y-2)=2(y+12)-2

We move all terms to the left:

8y-5(y-2)-(2(y+12)-2)=0

We multiply parentheses

8y-5y-(2(y+12)-2)+10=0



We calculate terms in parentheses: -(2(y+12)-2), so:

2(y+12)-2

We multiply parentheses

2y+24-2

We add all the numbers together, and all the variables

2y+22

Back to the equation:

-(2y+22)



We add all the numbers together, and all the variables

3y-(2y+22)+10=0

We get rid of parentheses

3y-2y-22+10=0

We add all the numbers together, and all the variables

y-12=0

We move all terms containing y to the left, all other terms to the right

y=12

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