8y-5-2y=-3(-2y+1)-2

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Solution for 8y-5-2y=-3(-2y+1)-2 equation: 



8y-5-2y=-3(-2y+1)-2

We move all terms to the left:

8y-5-2y-(-3(-2y+1)-2)=0

We add all the numbers together, and all the variables

6y-(-3(-2y+1)-2)-5=0



We calculate terms in parentheses: -(-3(-2y+1)-2), so:

-3(-2y+1)-2

We multiply parentheses

6y-3-2

We add all the numbers together, and all the variables

6y-5

Back to the equation:

-(6y-5)



We get rid of parentheses

6y-6y+5-5=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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