8y-6(y-3)=3(y+1)

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Solution for 8y-6(y-3)=3(y+1) equation: 



8y-6(y-3)=3(y+1)

We move all terms to the left:

8y-6(y-3)-(3(y+1))=0

We multiply parentheses

8y-6y-(3(y+1))+18=0



We calculate terms in parentheses: -(3(y+1)), so:

3(y+1)

We multiply parentheses

3y+3

Back to the equation:

-(3y+3)



We add all the numbers together, and all the variables

2y-(3y+3)+18=0

We get rid of parentheses

2y-3y-3+18=0

We add all the numbers together, and all the variables

-1y+15=0

We move all terms containing y to the left, all other terms to the right

-y=-15

y=-15/-1

y=+15

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