8y-7y+3y+4y=2(y-5)

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Solution for 8y-7y+3y+4y=2(y-5) equation: 



8y-7y+3y+4y=2(y-5)

We move all terms to the left:

8y-7y+3y+4y-(2(y-5))=0

We add all the numbers together, and all the variables

8y-(2(y-5))=0



We calculate terms in parentheses: -(2(y-5)), so:

2(y-5)

We multiply parentheses

2y-10

Back to the equation:

-(2y-10)



We get rid of parentheses

8y-2y+10=0

We add all the numbers together, and all the variables

6y+10=0

We move all terms containing y to the left, all other terms to the right

6y=-10

y=-10/6

y=-1+2/3

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