8y-8(y-1)=6-(16y-4)-10

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Solution for 8y-8(y-1)=6-(16y-4)-10 equation: 



8y-8(y-1)=6-(16y-4)-10

We move all terms to the left:

8y-8(y-1)-(6-(16y-4)-10)=0

We multiply parentheses

8y-8y-(6-(16y-4)-10)+8=0



We calculate terms in parentheses: -(6-(16y-4)-10), so:

6-(16y-4)-10

determiningTheFunctionDomain
-(16y-4)+6-10

We add all the numbers together, and all the variables

-(16y-4)-4

We get rid of parentheses

-16y+4-4

We add all the numbers together, and all the variables

-16y

Back to the equation:

-(-16y)



We add all the numbers together, and all the variables

-(-16y)+8=0

We get rid of parentheses

16y+8=0

We move all terms containing y to the left, all other terms to the right

16y=-8

y=-8/16

y=-1/2

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